n^2+102n-18=0

Solution for n^2+102n-18=0 equation:

n^2+102n-18=0

a = 1; b = 102; c = -18;
Δ = b2-4ac
Δ = 1022-4·1·(-18)
Δ = 10476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10476}=\sqrt{36*291}=\sqrt{36}*\sqrt{291}=6\sqrt{291}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-6\sqrt{291}}{2*1}=\frac{-102-6\sqrt{291}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+6\sqrt{291}}{2*1}=\frac{-102+6\sqrt{291}}{2}
$